Problem:
 0(q0(0(x1))) -> 0(0(q0(x1)))
 0(q0(1(x1))) -> 0(1(q0(x1)))
 1(q0(0(x1))) -> 0(0(q1(x1)))
 1(q0(1(x1))) -> 0(1(q1(x1)))
 1(q1(0(x1))) -> 1(0(q1(x1)))
 1(q1(1(x1))) -> 1(1(q1(x1)))
 0(q1(0(x1))) -> 0(0(q2(x1)))
 0(q1(1(x1))) -> 0(1(q2(x1)))
 1(q2(0(x1))) -> 1(0(q2(x1)))
 1(q2(1(x1))) -> 1(1(q2(x1)))
 0(q2(x1)) -> q3(1(x1))
 1(q3(x1)) -> q3(1(x1))
 0(q3(x1)) -> q4(0(x1))
 1(q4(x1)) -> q4(1(x1))
 0(q4(0(x1))) -> 1(0(q5(x1)))
 0(q4(1(x1))) -> 1(1(q5(x1)))
 1(q5(0(x1))) -> 0(0(q1(x1)))
 1(q5(1(x1))) -> 0(1(q1(x1)))
 0(q5(x1)) -> q6(0(x1))
 1(q6(x1)) -> q6(1(x1))
 1(q7(0(x1))) -> 0(0(q8(x1)))
 1(q7(1(x1))) -> 0(1(q8(x1)))
 0(q8(x1)) -> 0(q0(x1))
 1(q8(0(x1))) -> 1(0(q8(x1)))
 1(q8(1(x1))) -> 1(1(q8(x1)))
 0(q6(x1)) -> q9(0(x1))
 0(q9(0(x1))) -> 1(0(q7(x1)))
 0(q9(1(x1))) -> 1(1(q7(x1)))
 1(q9(x1)) -> q9(1(x1))
 h(q0(x1)) -> h(0(q0(x1)))
 q0(h(x1)) -> q0(0(h(x1)))
 h(q1(x1)) -> h(0(q1(x1)))
 q1(h(x1)) -> q1(0(h(x1)))
 h(q2(x1)) -> h(0(q2(x1)))
 q2(h(x1)) -> q2(0(h(x1)))
 h(q3(x1)) -> h(0(q3(x1)))
 q3(h(x1)) -> q3(0(h(x1)))
 h(q4(x1)) -> h(0(q4(x1)))
 q4(h(x1)) -> q4(0(h(x1)))
 h(q5(x1)) -> h(0(q5(x1)))
 q5(h(x1)) -> q5(0(h(x1)))
 h(q6(x1)) -> h(0(q6(x1)))
 q6(h(x1)) -> q6(0(h(x1)))

Proof:
 Bounds Processor:
  bound: 1
  enrichment: match
  automaton:
   final states: {13,12,11,10,9,8,7,6,5,4}
   transitions:
    q91(29) -> 30*
    11(36) -> 37*
    11(38) -> 39*
    11(28) -> 29*
    01(18) -> 19*
    q01(20) -> 21*
    q01(17) -> 18*
    q01(26) -> 27*
    00(2) -> 4*
    00(1) -> 4*
    00(3) -> 4*
    q00(2) -> 7*
    q00(1) -> 7*
    q00(3) -> 7*
    10(2) -> 5*
    10(1) -> 5*
    10(3) -> 5*
    q10(2) -> 8*
    q10(1) -> 8*
    q10(3) -> 8*
    q20(2) -> 9*
    q20(1) -> 9*
    q20(3) -> 9*
    q30(2) -> 10*
    q30(1) -> 10*
    q30(3) -> 10*
    q40(2) -> 11*
    q40(1) -> 11*
    q40(3) -> 11*
    q50(2) -> 12*
    q50(1) -> 12*
    q50(3) -> 12*
    q60(2) -> 13*
    q60(1) -> 13*
    q60(3) -> 13*
    q70(2) -> 1*
    q70(1) -> 1*
    q70(3) -> 1*
    q80(2) -> 2*
    q80(1) -> 2*
    q80(3) -> 2*
    q90(2) -> 3*
    q90(1) -> 3*
    q90(3) -> 3*
    h0(2) -> 6*
    h0(1) -> 6*
    h0(3) -> 6*
    1 -> 36,20
    2 -> 28,17
    3 -> 38,26
    19 -> 4*
    21 -> 18*
    27 -> 18*
    30 -> 39,29,5
    37 -> 29*
    39 -> 29*
  problem:
   
  Qed